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    1. 新聞中心

      EEPW首頁 > 嵌入式系統(tǒng) > 牛人業(yè)話 > 伽利略開發(fā)板和BeeMail(三):對象

      伽利略開發(fā)板和BeeMail(三):對象

      作者:EEPW編譯 時間:2014-11-25 來源:電子產(chǎn)品世界 收藏

        原型擴(kuò)展板有利于UNO用于初步檢驗(yàn)和板的轉(zhuǎn)移,從UNO的轉(zhuǎn)移可以確定,板的I/O引腳在嵌入式啟動和Arduino草圖啟動期間處于上拉狀態(tài)(取決于5V還是3.3V電壓)。

      本文引用地址:http://www.biyoush.com/article/265933.htm

        上面所說只是在理想狀態(tài)下的負(fù)邏輯,但馬達(dá)系統(tǒng)其實(shí)并不太適用。這里我按照GPIO的思路將引腳初始化為高電平,看看能不能找出其他辦法。

        代碼部分

        以下代碼僅為對蜜蜂基于電位計作為輸入的測試。若對蜜蜂不加干涉,程序自動上鎖,我在這里遇到了麻煩。我去檢查串聯(lián)端口和端口是否正常,可直到現(xiàn)在我仍舊不清楚到底是哪里出了問題。

        //------------------------------------------------------------ START LICENSE

        /*The MIT License (MIT)

        Copyright (c) 2014 Carlyn Maw

        特此授權(quán)許可,在此情況下本軟件免費(fèi),并允許任何人復(fù)制此軟件及相關(guān)文檔,不限制銷售,任何人有權(quán)使用、復(fù)制、修改、合并、出版、發(fā)行、授予執(zhí)照或銷售軟件副本,供任何對其有幫助的使用者使用。

        以上版權(quán)聲明和許可聲明包括軟件所有副本和可觀部分。

        軟件未加任何明指或暗指的擔(dān)保,按現(xiàn)狀出售,但不限于為特定目的和不侵權(quán)的適銷性及適用性的擔(dān)保。

        在任何情況下,作者或版權(quán)持有人,都無權(quán)要求任何索賠或有關(guān)損害賠償?shù)钠渌?zé)任,不管在本軟件的使用上或其他買賣交易中是否涉及合同、侵權(quán)或其他行為。

        */

        // ---------------------------------------------------------------- END LICENSE

        //This code is testing code for the circut to make sure all of the

        //physical Arduino I/O is working. It checks a potentiometer or other

        //sensors on the AO PIN and equates it to the future number of mails

        //in the inbox.

        //On each pin 9, 10 and 11 are 220 Ohm resistors leading to the bases of

        //PN2222A transistors. The collector is attached to the motor and the

        //emitter to ground.

        //------------------------------------------------- OUTPUTS AND THEIR VARIABLES

        //the total number of bees bing controlled

        const int beeTotalNumber = 3;

        int beePins[beeTotalNumber] = {9, 10, 11 };

        //INPUTS AND THEIR VARIABLES

        int howManyNewEmails = 0;

        //-------------------------------------------------------- GLOBAL BEE SETTINGS

        //the number of emails the bees hit maximum freakout.

        //ideally it should be divisible by the number of

        //beeActivityLevels

        int maxBeeVar = 1023;

        //how many different states the Bees can be in

        const int beeActivityLevels = 16;

        //The area that dictates the 16 BeeActivityLevels.

        int b[beeActivityLevels][beeTotalNumber] =

        {

        { 0, 0, 0 },

        { 0, 0, 50 },

        { 0, 50, 50 },

        { 50, 50, 50 },

        { 50, 50, 100 },

        { 50, 100, 100 },

        { 100, 100, 100 },

        { 100, 100, 150 },

        { 100, 150, 150 },

        { 150, 150, 150 },

        { 150, 150, 200 },

        { 150, 200, 200 },

        { 200, 200, 200 },

        { 200, 200, 250 },

        { 200, 250, 250 },

        { 255, 255, 255 },

        };

        //---------------------------------------------------------------------- SETUP

        void setup() {

        Serial.begin(9600);

        }

        //----------------------------------------------------------------------- LOOP

        void loop() {

        //get the data determining bee behavior

        howManyNewEmails = analogRead(A0);

        //Serial.println(howManyNewEmails);

        //update the bees

        updateBees(howManyNewEmails, maxBeeVar);

        //mini-pause

        delay(10);

        }

        //---------------------------------------------------------------- updateBees()

        void updateBees(int v, int maxVal) {

        //ignore any values of V above maximum freakout level

        // v = min(v, maxVal); does not work in Intel Galileo MacOS IDE

        if (v > maxVal) {

        v = maxVal;

        }

        //map the newly constrained V to the beeActivityLevel array

        //the top value is 1 less than the number than the array size

        //because the an array starts with the index number 0

        int mappedV = map(v, 0, maxVal, 0, beeActivityLevels-1);

        //Serial.println(mappedV);

        //for each bee, get the value it supposed to be and set it there

        for (int i=0; i <= beeTotalNumber-1; i++){

        //Serial.println(b[mappedV][i]);

        analogWrite(beePins[i], b[mappedV][i]);

        }

        }

      電容器相關(guān)文章:電容器原理



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