今天這個就是簡單的控制8*8LED點陣亮0~F這16個數(shù)字，暫時不加左移啊~~，上移啊~~以及16*16的點陣呢~~

不過也就這些天都發(fā)出來吧~~

呵呵~~

8*8LED點陣顯示0~F（這里是靜態(tài)顯示）

注意：

用Proteus仿真開始還真的不知道那個是行，那個是列~~

還得浪費我時間一點點看人家別人的東東~~

1）紅色LED上邊為列，下邊為行（其它顏色的正好相反，上為行，下為列~~）

2）對于紅色來說，上邊的列最低位在最右邊；下邊的行最低位也是恰好相反，在最左邊（一會看圖就知道了，我的就寫反了~~正好可以反過來看了~~）

基本上就這么兩點的注意事項~~

然后就是程序了：

LED.c

//------------------------------------------------------------------------------
//以前還真的沒仿真過LED點陣，今天正好沒事情做~~
//注意一點吧，紅色的上為列，下為行，其它顏色正好相反~~（前提是我也沒記錯的情況下~~呵呵，剛試驗了一下，對的~~）
#include"reg52.h"
#include"delay.h"
#include"macroandconst.h"
//------------------------------------------------------------------------------
#define ROW P0
#define LINE P2
uchar code row[]={0xfe,0xfd,0xfb,0xf7,0xef,0xdf,0xbf,0x7f};//送行
uchar code line[16][8]={
{0x1c,0x22,0x22,0x22,0x22,0x22,0x22,0x1c},//0 注意：這里的數(shù)據(jù)是翻轉(zhuǎn)的，因為對于紅色來說，這里上邊為列，最低位在最右邊，下邊為行，最低位在最左邊
{0x08,0x0c,0x08,0x08,0x08,0x08,0x08,0x1c},//1
{0x1c,0x22,0x22,0x10,0x08,0x04,0x02,0x3e},//2
{0x1c,0x22,0x20,0x18,0x20,0x20,0x22,0x1c},//3
{0x10,0x18,0x14,0x14,0x12,0x7c,0x10,0x38},//4
{0x3e,0x02,0x02,0x1e,0x20,0x20,0x20,0x1c},//5
{0x1c,0x22,0x02,0x1e,0x22,0x22,0x22,0x1c},//6
{0x3e,0x12,0x10,0x08,0x08,0x08,0x08,0x08},//7
{0x1c,0x22,0x22,0x1c,0x22,0x22,0x22,0x1c},//8
{0x1c,0x22,0x22,0x22,0x3c,0x20,0x22,0x1c},//9
{0x08,0x08,0x18,0x14,0x14,0x3c,0x24,0x66},//A
{0x1e,0x24,0x24,0x1c,0x24,0x24,0x24,0x1e},//B
{0x3c,0x22,0x02,0x02,0x02,0x02,0x22,0x1c},//C
{0x1e,0x24,0x24,0x24,0x24,0x24,0x24,0x1e},//D
{0x3e,0x24,0x14,0x1c,0x14,0x04,0x24,0x3e},//E
{0x3e,0x24,0x14,0x1c,0x14,0x04,0x04,0x0e},//F
};
uchar num;
uchar times;
uchar count;
//------------------------------------------------------------------------------
//main
void main()
{
while(1)
{
for(num=0;num<16;num++)
{
for(times=0;times<50;times++)
{
for(count=0;count<8;count++)//刷新行和列
{
ROW=0XFF;//每次都要消影，就是讓行都為低電平
LINE=line[num][count];
ROW=row[count];
delay(2);//延時100ms
}
}
}
}
}